Jquery Dynamic Table Create?

July 30, 2023 Post a Comment

How to create Dynamic table using JQuery I created with .append but problem is when i am clicking on again so create anther table but i want add in to a same table so how can i do

Solution 1:

Try my answer

$(function () {
    $("#addProduct").click(function () {
          var table = $('<table></table>').addClass('foo');
        for (var i = 0; i < 10; i++) {
                row = $('<tr></tr>');
                for (var j = 0; j < 10; j++) {
                    var rowData = $('<td></td>').addClass('bar').text('result ' + j);
                    row.append(rowData);
                }
                table.append(row);
            }

        if ($('table').length) {
             $("#someContainer tr:first").after(row);
        }
        else {
            $('#someContainer').append(table);
        }
    });
});

Solution 2:

try this

$(function() {  
    $("#addProduct").click(function() {
        if($('#someContainer table').length > 0)
        {
            var row = $('<tr></tr>');
            for(i=0; i<10; i++){
                var row1 = $('<td></td>').addClass('bar').text('result ' + i);
                row.append(row1);
            }
            $('#someContainer table').append(row);
        }
        else
        {
            var table = $('<table></table>').addClass('foo');
            for(i=0; i<10; i++){
                var row = $('<tr></tr>');
                for(i=0; i<10; i++){
                    var row1 = $('<td></td>').addClass('bar').text('result ' + i);
                    table.append(row);
                    row.append(row1);
                }
            }
            $('#someContainer').append(table);
        }
    });
});

live demo here.

Solution 3:

If you want to execute it for only once try using .one() in jQuery.

$(function () {
    $("#addProduct").one("click", function () {

        var table = $('<table></table>').addClass('foo');
        for (i = 0; i < 10; i++) {
            var row = $('<tr></tr>');
            for (i = 0; i < 10; i++) {
                var row1 = $('<td></td>').addClass('bar').text('result ' + i);
                table.append(row);
                row.append(row1);
            }
        }
        $('#someContainer').append(table);
    });
});

Check JSFiddle.

Solution 4:

$(function () {
    $("#addProduct").click(function () {
    var table
    if($('#someContainer').find("table").length > 0){
          table =$('#someContainer').find("table");
    }else{
          table = $('<table></table>').addClass('foo');
    }

        for (i = 0; i < 10; i++) {
            var row = $('<tr></tr>');
            for (i = 0; i < 10; i++) {
                var row1 = $('<td></td>').addClass('bar').text('result ' + i);
                table.append(row);
                row.append(row1);
            }
        }
        $('#someContainer').append(table);
    });
});

try this one DEMO

Solution 5:

<html><head></head><body><tableid="game_table"border="1"></table><scriptlanguage="JavaScript">

gt = document.getElementById('game_table'),
 i = 0, 
  frag = document.createDocumentFragment(),
   tr = document.createElement('tr'),
    td = document.createElement('td');

while (i<10) {
 var _tr = tr.cloneNode(),
  j = 0;
   while (j<10) {
    _tr.appendChild(td.cloneNode());
     var min = 1 ;
      var max = 3 ;
       var a = Math.floor( Math.random() * (max + 1 - min) ) + min ;

var temp = document.createElement('div');
 temp.innerHTML = "str";
  _tr.appendChild(temp.firstChild);
    j++;
     }

frag.appendChild(_tr);
 i++;
  }
   gt.appendChild(frag);

  </script></body></html>

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